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3d Geometry

JEE Main 2026 (Online) 6th April Evening Shift

MCQ+4 / -12026

The shortest distance between the lines $\frac{x-4}{1}=\frac{y-3}{2}=\frac{z-2}{-3}$ and $\frac{x+2}{2}=\frac{y-6}{4}=\frac{z-5}{-5}$ is:

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