Jee Main
3d Geometry
JEE Main 2023 (Online) 15th April Morning Shift
MCQ+4 / -12023
Let the system of linear equations
$-x+2 y-9 z=7$
$-x+3 y+7 z=9$
$-2 x+y+5 z=8$
$-3 x+y+13 z=\lambda$
has a unique solution $x=\alpha, y=\beta, z=\gamma$. Then the distance of the point
$(\alpha, \beta, \gamma)$ from the plane $2 x-2 y+z=\lambda$ is :
$-x+2 y-9 z=7$
$-x+3 y+7 z=9$
$-2 x+y+5 z=8$
$-3 x+y+13 z=\lambda$
has a unique solution $x=\alpha, y=\beta, z=\gamma$. Then the distance of the point
$(\alpha, \beta, \gamma)$ from the plane $2 x-2 y+z=\lambda$ is :
