Jee Main
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JEE Main 2022 (Online) 26th June Evening Shift
MCQ+4 / -12022
If m is the slope of a common tangent to the curves \({{{x^2}} \over {16}} + {{{y^2}} \over 9} = 1\) and \({x^2} + {y^2} = 12\), then \(12{m^2}\) is equal to :
Jee Main
JEE Main 2022 (Online) 26th June Evening Shift
If m is the slope of a common tangent to the curves \({{{x^2}} \over {16}} + {{{y^2}} \over 9} = 1\) and \({x^2} + {y^2} = 12\), then \(12{m^2}\) is equal to :