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Differential Equations

JEE Main 2022 (Online) 28th June Morning Shift

MCQ+4 / -12022

Let y = y(x) be the solution of the differential equation \(x(1 - {x^2}){{dy} \over {dx}} + (3{x^2}y - y - 4{x^3}) = 0\), \(x > 1\), with \(y(2) = - 2\). Then y(3) is equal to :

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