Jee Main
Differential Equations
JEE Main 2022 (Online) 28th June Morning Shift
MCQ+4 / -12022
Let y = y(x) be the solution of the differential equation \(x(1 - {x^2}){{dy} \over {dx}} + (3{x^2}y - y - 4{x^3}) = 0\), \(x > 1\), with \(y(2) = - 2\). Then y(3) is equal to :
