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Differential Equations

JEE Main 2022 (Online) 28th June Evening Shift

MCQ+4 / -12022

Let x = x(y) be the solution of the differential equation

\(2y\,{e^{x/{y^2}}}dx + \left( {{y^2} - 4x{e^{x/{y^2}}}} \right)dy = 0\) such that x(1) = 0. Then, x(e) is equal to :

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