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Limits Continuity And Differentiability

JEE Main 2021 (Online) 27th July Morning Shift

MCQ+4 / -12021
Let f : R \(\to\) R be a function such that f(2) = 4 and f'(2) = 1. Then, the value of \(\mathop {\lim }\limits_{x \to 2} {{{x^2}f(2) - 4f(x)} \over {x - 2}}\) is equal to :

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