Jee Main
Limits Continuity And Differentiability
JEE Main 2021 (Online) 27th July Evening Shift
MCQ+4 / -12021
The value of
\(\mathop {\lim }\limits_{x \to 0} \left( {{x \over {\root 8 \of {1 - \sin x} - \root 8 \of {1 + \sin x} }}} \right)\) is equal to :
\(\mathop {\lim }\limits_{x \to 0} \left( {{x \over {\root 8 \of {1 - \sin x} - \root 8 \of {1 + \sin x} }}} \right)\) is equal to :