Jee Main
Limits Continuity And Differentiability
JEE Main 2021 (Online) 27th August Morning Shift
MCQ+4 / -12021
If \(\alpha\), \(\beta\) are the distinct roots of x2 + bx + c = 0, then
\(\mathop {\lim }\limits_{x \to \beta } {{{e^{2({x^2} + bx + c)}} - 1 - 2({x^2} + bx + c)} \over {{{(x - \beta )}^2}}}\) is equal to :
\(\mathop {\lim }\limits_{x \to \beta } {{{e^{2({x^2} + bx + c)}} - 1 - 2({x^2} + bx + c)} \over {{{(x - \beta )}^2}}}\) is equal to :