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Inverse Trigonometric Functions

JEE Main 2021 (Online) 27th August Morning Shift

MCQ+4 / -12021
If \({({\sin ^{ - 1}}x)^2} - {({\cos ^{ - 1}}x)^2} = a\); 0 < x < 1, a \(\ne\) 0, then the value of 2x2 \(-\) 1 is :

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