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Inverse Trigonometric Functions

JEE Main 2026 (Online) 6th April Morning Shift

MCQ+4 / -12026

Let $0<\alpha<1, \beta=\frac{1}{3 \alpha}$ and $\tan ^{-1}(1-\alpha)+\tan ^{-1}(1-\beta)=\frac{\pi}{4}$. Then $6(\alpha+\beta)$ is equal to:

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