Jee Main
Inverse Trigonometric Functions
JEE Main 2026 (Online) 6th April Morning Shift
MCQ+4 / -12026
Let $0<\alpha<1, \beta=\frac{1}{3 \alpha}$ and $\tan ^{-1}(1-\alpha)+\tan ^{-1}(1-\beta)=\frac{\pi}{4}$. Then $6(\alpha+\beta)$ is equal to:
Jee Main
JEE Main 2026 (Online) 6th April Morning Shift
Let $0<\alpha<1, \beta=\frac{1}{3 \alpha}$ and $\tan ^{-1}(1-\alpha)+\tan ^{-1}(1-\beta)=\frac{\pi}{4}$. Then $6(\alpha+\beta)$ is equal to: