Jee Main
Differential Equations
JEE Main 2021 (Online) 20th July Morning Shift
MCQ+4 / -12021
Let y = y(x) be the solution of the differential equation \({e^x}\sqrt {1 - {y^2}} dx + \left( {{y \over x}} \right)dy = 0\), y(1) = \(-\)1. Then the value of (y(3))2 is equal to :
