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Differential Equations

JEE Main 2021 (Online) 1st September Evening Shift

MCQ+4 / -12021
If y = y(x) is the solution curve of the differential equation \({x^2}dy + \left( {y - {1 \over x}} \right)dx = 0\) ; x > 0 and y(1) = 1, then \(y\left( {{1 \over 2}} \right)\) is equal to :

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