Work, Energy and Power PYQs - Last 10 Years
COMEDK / Physics / Mechanics / 17 recent questions
PhysicsMechanics2017-2026
Practice 17 COMEDK Physics questions from Work, Energy and Power. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.
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Last 10 Years Work, Energy and Power Questions
Showing 17 of 17 filtered questions.
1Work Energy And Power
A ball falls under gravity from a height of 10 m with an initial downward velocity u . It loses one third of its energy in collision and then rises back to 5 m . The initial velocity u is $\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)$
MCQ+1 / -02026
2Work Energy And Power
A block of mass 1.5 kg moves along the floor of a hall with a speed of $5 \mathrm{~ms}^{-1}$. It strikes an uncompressed spring and compresses it till the block becomes motionless. If the force constant of the spring is $10000 \mathrm{Nm}^{...
MCQ+1 / -02026
3Work Energy And Power
Momentum of a body is increased to three times its original value. By what percentage will its kinetic energy change?
MCQ+1 / -02025
4Work Energy And Power
The power of a gun which fires 120 bullet per minute with a velocity \(120 \mathrm{~ms}^{-1}\) is : (given the mass of each bullet is \(100 \mathrm{~g}\))
MCQ+1 / -02024
5Work Energy And Power
When water falls from a height of \(80 \mathrm{~m}\) at the rate of \(20 \mathrm{~kg} \mathrm{~s}^{-1}\) to operate a turbine the losses due to frictional force are \(20 \%\) of input energy. How much power is generated by the turbine?
MCQ+1 / -02024
6Work Energy And Power
A scooter moves with a speed of \(7 \mathrm{~ms}^{-1}\), on a straight road and is stopped by applying the brakes. Before stopping, the scooter travels \(10 \mathrm{~m}\). If the weight of the scooter is \(\mathrm{W}\), then the total resis...
MCQ+1 / -02024
7Work Energy And Power
An electric motor raises a mass of \(1.5 \mathrm{~kg}\), a distance of \(1.128 \mathrm{~m}\) in time of \(4.79 \mathrm{~s}\). Calculate the power to an appropriate significant figures.
(take \(g=9.81 \mathrm{~ms}^{-2}\))
(take \(g=9.81 \mathrm{~ms}^{-2}\))
MCQ+1 / -02024
8Work Energy And Power
An object of mass \(3 \mathrm{~kg}\) moves due to an applied constant force such that its position along \(\mathrm{X}\) axis is given by \(x=\frac{t^3}{3}\) where \(x\) is in meters and $t$ in seconds. The work done in 1 second is
MCQ+1 / -02024
9Work Energy And Power
If reaction is \(\mathrm{R}\) and coefficient of friction is \(\mu\), what is work done against friction in moving a body by distance \(\mathrm{d}\) ?
MCQ+1 / -02023
10Work Energy And Power
A long spring, when stretched by a distance \(x\), has potential energy \(U\). On increasing the stretching to \(n x\), the potential energy of the spring will be
MCQ+1 / -02023
11Work Energy And Power
A particle is projected at an angle \(30^{\circ}\) with horizontal having kinetic energy \(K\). The kinetic energy of the particle at highest point is.
MCQ+1 / -02023
12Work Energy And Power
A particle of mass \(m\) is moving in a horizontal circle of radius \(r\) under a centripetal force given by \(\left(\frac{-K}{r^2}\right)\), where \(K\) is a constant. Then
MCQ+1 / -02022
13Work Energy And Power
If kinetic energy of a body is increased by 300%, then percentage change in momentum will be
MCQ+1 / -02022
14Work Energy And Power
For motion under central forces, which quantity will be conserved?
MCQ+1 / -02021
15Work Energy And Power
Two masses of 1g and 9g are moving with equal kinetic energy. The ratio of magnitude of their momentum is
MCQ+1 / -02021
16Work Energy And Power
A force of 20 N is applied on a body of mass
5 kg resting on a horizontal plane. The body
gains a kinetic energy of 10 J after it moves a
distance 2 m. The frictional force is
5 kg resting on a horizontal plane. The body
gains a kinetic energy of 10 J after it moves a
distance 2 m. The frictional force is
MCQ+1 / -02020
17Work Energy And Power
A particle of mass m is moving in a horizontal
circle of radius R under a centripetal force equal
to \(-\frac{A}{R^2}\) (A = constant). The total energy of the particle is
circle of radius R under a centripetal force equal
to \(-\frac{A}{R^2}\) (A = constant). The total energy of the particle is
MCQ+1 / -02020