s is given by:

$ W = m \times g \times h $

Where:

$ m = 1.5\, \text{kg} $ (mass)

$ g = 9.81\, \text{m/s}^2 $ (acceleration due to gravity)

$ h = 1.128\, \text{m} $ (height)

Calculating:

$ W = 1.5\, \text{kg} \times 9.81\, \text{m/s}^2 \times 1.128\, \text{m} = 16.59852\, \text{J} $

Step 2: Calculate the Power

Power $ P $ is the work done divided by the time $ t $:

$ P = \frac{W}{t} $

Given $ t = 4.79\, \text{s} $:

$ P = \frac{16.59852\, \text{J}}{4.79\, \text{s}} \approx 3.465\, \text{W} $

Step 3: Determine Significant Figures

We need to express the power to the appropriate number of significant figures. Let's look at the significant figures in the given data:

Mass $ m = 1.5\, \text{kg} $ has 2 significant figures.

Height $ h = 1.128\, \text{m} $ has 4 significant figures.

Time $ t = 4.79\, \text{s} $ has 3 significant figures.

Acceleration $ g = 9.81\, \text{m/s}^2 $ has 3 significant figures.

The calculated work $ W $ and power $ P $ should be reported with the least number of significant figures from the given data, which is 2 significant figures (from the mass).

Therefore, we round the power to 2 significant figures:

$ P \approx 3.5\, \text{W} $

Answer: Option D: 3.5 W

Work Energy And Power

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