Binomial Theorem PYQs - Last 10 Years
BITSAT / Mathematics / Algebra / 10 recent questions
MathematicsAlgebra2016-2025
Practice 10 BITSAT Mathematics questions from Binomial Theorem. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.
10
PYQs on Page
Mathematics / Algebra
2020-2025
Year Range
Based on indexed question metadata
8
Last 5 Years
2021-2025
10
Last 10 Years
2016-2025
Recent Year Trend
2020
2021
2022
2023
2024
2025Latest year
20202 max PYQs/year2025
Question Types
10PYQs
MCQ100%
Difficulty Mix
#1 Unknown10
8 in last 5 years10 in last 10 years
Last 10 Years Binomial Theorem Questions
Showing 10 of 10 filtered questions.
1Binomial Theorem
What is the coefficient of $x^{50}$ in $(1+x)^{41}\left(1-x+x^2\right)^{40}$.
MCQ+3 / -12025
2Binomial Theorem
If ${ }^n C_{n-r}+3 \cdot{ }^n C_{n-r+1}+3 \cdot{ }^n C_{n-r+2} +{ }^n C_{n-r+3}={ }^x C_r$, then the value of $x$ is
MCQ+3 / -12025
3Binomial Theorem
The coefficient of $ x^{2} $ term in the binomial expansion of $ \left(\frac{1}{3} x^{\frac{1}{2}}+x^{\frac{-1}{4}}\right)^{10} $ is
MCQ+3 / -12024
4Binomial Theorem
$$\sum_\limits{\substack{i, j=0 \\ i \neq j}}^n{ }^n C_i{ }^n C_j$$ is equal to
MCQ+3 / -12023
5Binomial Theorem
The sum of the coefficients of all odd degree terms in the expansion of \(\left(x+\sqrt{x^3-1}\right)^5 +\left(x-\sqrt{x^3-1}\right)^5, x>1\) is
MCQ+3 / -12023
6Binomial Theorem
If the sum of the coefficients in the expansion of (x + y)n is 1024, then the value of the greatest coefficient in the expansion is
MCQ+3 / -12022
7Binomial Theorem
The number of terms in the expansion of \({(1 + 5\sqrt {2x} )^9} + {(1 - 5\sqrt {2x} )^9}\) is
MCQ+3 / -12022
8Binomial Theorem
\({{{C_1}} \over {{C_0}}} + 2{{{C_2}} \over {{C_1}}} + 3{{{C_3}} \over {{C_2}}} + 4{{{C_4}} \over {{C_3}}} + ....20{{{C_{20}}} \over {{C_{19}}}} =\)
MCQ+3 / -12021
9Binomial Theorem
The coefficient of x8 in the polynomial (x \(-\) 1) (x \(-\) 2) ..... (x \(-\) 10)
MCQ+3 / -12020
10Binomial Theorem
The value of \({}^{47}{C_4} + \sum\limits_{r = 1}^5 {{}^{52 - r}{C_3}}\) is equal to
MCQ+3 / -12020