BitsatBinomial TheoremBITSAT 2020MCQ+3 / -12020The value of \({}^{47}{C_4} + \sum\limits_{r = 1}^5 {{}^{52 - r}{C_3}}\) is equal toA\({}^{47}{C_6}\)B\({}^{52}{C_5}\)C\({}^{52}{C_4}\)DNone of theseCheck AnswerClear SelectionReveal AnswerShow Explanation
