BitsatBinomial TheoremBITSAT 2023MCQ+3 / -12023$$\sum_\limits{\substack{i, j=0 \\ i \neq j}}^n{ }^n C_i{ }^n C_j$$ is equal toA\(2^{2 n}-{ }^{2 n} C_n\)B\(2^{2 n-1}-{ }^{2 n-1} C_{n-1}\)C\(2^{2 n}-\frac{1}{2}\left({ }^{2 n} C_n\right)\)D\(2^{n-1}+2\left({ }^{2 n-1} C_n\right)\)Check AnswerClear SelectionReveal AnswerShow Explanation
