Bitsat
Differentiation
BITSAT 2021
MCQ+3 / -12021
If \(y = \sin \left( {2{{\tan }^{ - 1}}\sqrt {{{1 - x} \over {1 + x}}} } \right)\), then \({{dy} \over {dx}}\) is :
Bitsat
BITSAT 2021
If \(y = \sin \left( {2{{\tan }^{ - 1}}\sqrt {{{1 - x} \over {1 + x}}} } \right)\), then \({{dy} \over {dx}}\) is :