BitsatDifferentiationBITSAT 2024MCQ+3 / -12024If $ x \sqrt{1+y}+y \sqrt{1+x}=0 $, then $ \frac{d y}{d x}= $A$ \frac{x+1}{x} $B$ \frac{1}{1+x} $C$ \frac{-1}{(1+x)^{2}} $D$ \frac{x}{1+x} $Check AnswerClear SelectionReveal AnswerShow Explanation
