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Application Of Derivatives
WB JEE 2024
MCQ+1 / -0.252024
\(f(x)=\cos x-1+\frac{x^2}{2!}, x \in \mathbb{R}\) সেক্ষেত্রে f(x) হবে
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WB JEE 2024
\(f(x)=\cos x-1+\frac{x^2}{2!}, x \in \mathbb{R}\) সেক্ষেত্রে f(x) হবে