Wb Jee
Differential Equations
WB JEE 2010
SUBJECTIVE+2 / -02010
If \({{dy} \over {dx}} + \sqrt {{{1 - {y^2}} \over {1 - {x^2}}}} = 0\), prove that \(x\sqrt {1 - {y^2}} + y\sqrt {1 - {x^2}} = A\), where A is a constant.
Wb Jee
WB JEE 2010
If \({{dy} \over {dx}} + \sqrt {{{1 - {y^2}} \over {1 - {x^2}}}} = 0\), prove that \(x\sqrt {1 - {y^2}} + y\sqrt {1 - {x^2}} = A\), where A is a constant.