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Trigonometric Functions And Equations

WB JEE 2009

SUBJECTIVE+2 / -02009

Show that \({{\sin \theta } \over {\cos 3\theta }} + {{\sin 3\theta } \over {\cos 9\theta }} + {{\sin 9\theta } \over {\cos 27\theta }} = {1 \over 2}(\tan 27\theta - \tan \theta )\)

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