Wb Jee
Trigonometric Functions And Equations
WB JEE 2026
MCQ+1 / -0.252026
$x^2+y^2=\frac{x \cos 3 \theta+y \sin 3 \theta}{\cos ^3 \theta}=\frac{y \cos 3 \theta-x \sin 3 \theta}{\sin ^3 \theta}$ সমীকরণগুলি থেকে $\theta$ অপনয়ন করলে হবে
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