Carboxylic Acids and Its Derivatives
TS EAMCET / Chemistry / Organic Chemistry / 18 questions
ChemistryOrganic Chemistry18 PYQs
Practice 18 TS EAMCET Chemistry questions from Carboxylic Acids and Its Derivatives. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.
18
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Chemistry / Organic Chemistry
2020-2025
Year Range
Based on indexed question metadata
13
Last 5 Years
2021-2025
18
Last 10 Years
2016-2025
Recent Year Trend
2020
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2025Latest year
20205 max PYQs/year2025
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18PYQs
MCQ100%
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#1 Unknown18
13 in last 5 years18 in last 10 years
Carboxylic Acids and Its Derivatives Questions
Showing 18 of 18 questions on this page.
1Carboxylic Acids And Its Derivatives
What are $X$ and $Y$ respectively in the following reactions?
MCQ+1 / -02025
2Carboxylic Acids And Its Derivatives
Consider the following set of reactions
What are $A$ and $B$ respectively?
What are $A$ and $B$ respectively?
MCQ+1 / -02025
3Carboxylic Acids And Its Derivatives
Which of the following can undergo Hell-Volhard-Zelinsky reaction?
MCQ+1 / -02025
4Carboxylic Acids And Its Derivatives
What is $C$ in the given sequence of reactions?
MCQ+1 / -02024
5Carboxylic Acids And Its Derivatives
Formic acid on heating with concentrated $\mathrm{H}_{2} \mathrm{SO}_{4}$ at 373 K gives $X$, a colourless substance and $Y$, a good reducing agent. The number of $\sigma$ and $\pi$ bonds in $X, Y$ are respectively
MCQ+1 / -02024
6Carboxylic Acids And Its Derivatives
In the given reaction sequence sequence, $Z$ is
MCQ+1 / -02024
7Carboxylic Acids And Its Derivatives
$\mathrm{NH}_2 \mathrm{CONH}_2+2 \mathrm{H}_2 \mathrm{O} \rightarrow[\mathrm{X}] \rightleftharpoons 2 \mathrm{NH}_3+\mathrm{H}_2 \mathrm{O}+[\mathrm{Y}]$
The hybridisation of carbon in $X$ and $Y$ respectively are
The hybridisation of carbon in $X$ and $Y$ respectively are
MCQ+1 / -02024
8Carboxylic Acids And Its Derivatives
In the following reaction ' $C$ ' is an aromatic compound having substitutents $D$ and $E$. What are $D$ and $E$ ?
MCQ+1 / -02023
9Carboxylic Acids And Its Derivatives
The correct order of $\mathrm{p} K_a$ of the following is
\(\underset{\mathrm{I}}{\mathrm{CCl}_3 \mathrm{COOH}} \quad \underset{\mathrm{II}}{\mathrm{CF}_3 \mathrm{COOH}}\)
$$ \underset{\text { III }}{\mathrm{NO}_2 \mathrm{CH}_2 \mathrm{CO...
\(\underset{\mathrm{I}}{\mathrm{CCl}_3 \mathrm{COOH}} \quad \underset{\mathrm{II}}{\mathrm{CF}_3 \mathrm{COOH}}\)
$$ \underset{\text { III }}{\mathrm{NO}_2 \mathrm{CH}_2 \mathrm{CO...
MCQ+1 / -02022
10Carboxylic Acids And Its Derivatives
Which of the following set of compounds react with $\mathrm{NaHCO}_3$ ?
MCQ+1 / -02022
11Carboxylic Acids And Its Derivatives
The major product of the following reactions
MCQ+1 / -02022
12Carboxylic Acids And Its Derivatives
The reagent that can reduce the carboxylic acid group to the corresponding alcohol is
MCQ+1 / -02022
13Carboxylic Acids And Its Derivatives
$n$ - propanol on treatment with concentrated HBr gives $P$. The product $P$ on reaction with KCN gave the product $Q$. The product $Q$ on heating with aqueous acidic solution, furnished the product $R$. The product ' $R$ ' is
MCQ+1 / -02022
14Carboxylic Acids And Its Derivatives
\(\text { Predict } A \text { and } B \text { in the following reaction sequence : }\)
\(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{COOH}\)
$$ \xrightarrow[\text { Red phosphorus }]{\mathrm{Br}_2} A \xrightarrow{\ma...
\(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{COOH}\)
$$ \xrightarrow[\text { Red phosphorus }]{\mathrm{Br}_2} A \xrightarrow{\ma...
MCQ+1 / -02020
15Carboxylic Acids And Its Derivatives
\(\text { The major product formed in the following reaction is }\)
MCQ+1 / -02020
16Carboxylic Acids And Its Derivatives
\(\text { The major product in the following reaction is }\)
MCQ+1 / -02020
17Carboxylic Acids And Its Derivatives
\(\text { In the following reactions, } P, Q \text { and } R \text { are }\)
MCQ+1 / -02020
18Carboxylic Acids And Its Derivatives
What is the product $R$ in the following reaction sequence?
MCQ+1 / -02020
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