Ts Eamcet
Limits Continuity And Differentiability
TS EAMCET 2023 (Online) 14th May Morning Shift
MCQ+1 / -02023
\(\lim _{n \rightarrow \infty} \frac{1}{n^3} \sum_{k=1}^n\left(k^2 x\right)=\)
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