Ts Eamcet
Limits Continuity And Differentiability
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ+1 / -02025
If $f(x)=\left\{\begin{array}{cc}x^2\left|\cos \frac{\pi}{2}\right|, & x \neq 0 \\ 0, & x=0\end{array}\right.$, then at $x=2, f(x)$ is
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