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Limits Continuity And Differentiability

TS EAMCET 2020 (Online) 10th September Evening Shift

MCQ+1 / -02020

The value of ' $a$ ' for which the function


$f(x)=\left\{\begin{array}{cl}\frac{1-\cos 4 x}{x^2}, & x<0 \\ \frac{a}{\sqrt{x}}, & x=0 \text { is continuous at } x=0, \text { is } \\ \frac{\sqrt{16+\sqrt{x}}-4}{\sqrt{16+}} & \end{array}\right.$


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