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TS EAMCET 2020 (Online) 14th September Evening Shift

MCQ+1 / -02020

If $\frac{x^5-5}{x^3+x^2}=f(x)+\frac{A}{x}+\frac{B}{x^2}+\frac{C}{x+1}$, then the larger value of $K$ for which $f(K)+A+B+C=1$, is


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