Ts Eamcet
Functions
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ+1 / -02025
The domain and range of $f(x)=\frac{1}{\sqrt{|x|-x^2}}$ are $A$ and $B$ respectively. Then $A \cup B=$
Ts Eamcet
TG EAPCET 2025 (Online) 4th May Evening Shift
The domain and range of $f(x)=\frac{1}{\sqrt{|x|-x^2}}$ are $A$ and $B$ respectively. Then $A \cup B=$