Ts Eamcet
Differential Equations
TS EAMCET 2020 (Online) 11th September Morning Shift
MCQ+1 / -02020
The general solution of the differential equation $\left(1+y^2\right) d x=\left(\tan ^{-1} y-x\right) d y$ is
Ts Eamcet
TS EAMCET 2020 (Online) 11th September Morning Shift
The general solution of the differential equation $\left(1+y^2\right) d x=\left(\tan ^{-1} y-x\right) d y$ is