Ts Eamcet
Differential Equations
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ+1 / -02020
The solution of the differential equation $x d y-y d x=\sqrt{x^2+y^2} d x$, given that $y=1$ when $x=\sqrt{3}$, is
Ts Eamcet
TS EAMCET 2020 (Online) 11th September Evening Shift
The solution of the differential equation $x d y-y d x=\sqrt{x^2+y^2} d x$, given that $y=1$ when $x=\sqrt{3}$, is