TS EAMCET 2020 (Online) 10th September Morning Shift
TS EAMCET / 160 questions
2025Thu, Sep 10, 2020 3:30 AM160 PYQs
1Semiconductor Devices And Logic Gates
The Boolean expression of the circuit given in figure is
MCQ+1 / -02020
2Semiconductor Devices And Logic Gates
Which of the following depicts the output of the full wave rectifier with capacitor filter for the following AC input?
MCQ+1 / -02020
3Simple Harmonic Motion
For a particle executing SHM, determine the ratio of average acceleration of the particle between extreme position and equilibrium position w.r.t. the maximum acceleration.
MCQ+1 / -02020
4Units And Measurement And Dimensions
Due to an explosion underneath water, a bubble started oscillating. If this oscillation has time period $T$,which is proportional to $p^\alpha S^\beta E^\gamma$, where $p$ is static pressure, $S$ is density of water and $E$ is total energy ...
MCQ+1 / -02020
5Vector Algebra
If $0.5 \hat{\mathbf{i}}+0.8 \hat{\mathbf{j}}+c \hat{\mathbf{k}}$ is a unit vector, then $c$ is
MCQ+1 / -02020
6Wave Optics
On using red light $(\lambda=6600 \mathop {\rm{A}}\limits^{\rm{o}})$ in Young's double slit experiment, 60 fringes are observed in the field of view. If violet light ( $\lambda=4400 \mathop {\rm{A}}\limits^{\rm{o}}$ ) is used, the number of...
MCQ+1 / -02020
7Wave Optics
Young's double slit experiment is carried out by using green, red and blue light, one colour at a time. The fringe width recorded are $\beta_{G^{\prime}} \beta_{R^{\prime}} \beta_B$ respectively, then
MCQ+1 / -02020
8Waves
A bus moving with an uniform speed of $72 \mathrm{~km} / \mathrm{h}$ towards a building blows a horn of frequency 1.7 kHz . If speed of sound in air is $340 \mathrm{~m} / \mathrm{s}$, what will be the frequency of echo heard by bus driver?
MCQ+1 / -02020
9Work Energy And Power
When a body is acted upon by a resultant force, then the work done by the resultant force is equal to
MCQ+1 / -02020
10Work Energy And Power
A force acts on a body of mass 10 kg , resulting in its displacement given as $x=\left(\frac{t^3}{25}\right) \mathrm{m}$, where $t$ is the time in seconds. The work done by the force in 5 s is
MCQ+1 / -02020
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