Some Basic Concepts of Chemistry PYQs - Last 5 Years
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ChemistryPhysical Chemistry2022-2026
Practice 18 NEET Chemistry questions from Some Basic Concepts of Chemistry. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.
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Last 5 Years Some Basic Concepts of Chemistry Questions
Showing 18 of 18 filtered questions.
1Some Basic Concepts Of Chemistry
The amount of carbon dioxide evolved upon complete combustion of $116 g$ of $n$-butane is
(Given: atomic mass in amu $\mathrm{H}=1, \mathrm{C}=12$ and $\mathrm{O}=16$ )
(Given: atomic mass in amu $\mathrm{H}=1, \mathrm{C}=12$ and $\mathrm{O}=16$ )
MCQ+4 / -12026
2Some Basic Concepts Of Chemistry
The numbers 17.0145 and 21.0235 were rounded to three figures after the decimal point. The resulting numbers, respectively, are
MCQ+4 / -12026
3Some Basic Concepts Of Chemistry
The number of hydrogen atoms present in 5.4 g of urea is:
(Given: Molar mass of urea : $60 \mathrm{~g} \mathrm{~mol}^{-1}$
$\mathrm{N}_{\mathrm{A}}: 6.022 \times 10^{23}$ particles $\mathrm{mol}^{-1}$ )
(Given: Molar mass of urea : $60 \mathrm{~g} \mathrm{~mol}^{-1}$
$\mathrm{N}_{\mathrm{A}}: 6.022 \times 10^{23}$ particles $\mathrm{mol}^{-1}$ )
MCQ+4 / -12026
4Some Basic Concepts Of Chemistry
When $1 \mathrm{dm}^3$ of CO2 gas is passed over hot coke the volume of gaseous mixture after complete reaction at STP becomes $1.4 \mathrm{dm}^3$. The composition of the gaseous mixture at STP is :
MCQ+4 / -12026
5Some Basic Concepts Of Chemistry
Dalton's Atomic theory could not explain which of the following?
MCQ+4 / -12025
6Some Basic Concepts Of Chemistry
Among the following, choose the ones with equal number of atoms.
A. 212 g of $\mathrm{Na}_2 \mathrm{CO}_3(\mathrm{~s})$ [molar mass $=106 \mathrm{~g}$ ]
B. 248 g of $\mathrm{Na}_2 \mathrm{O}(\mathrm{s})$ [molar mass $=62 \mathrm{~g}$ ]
C. 2...
A. 212 g of $\mathrm{Na}_2 \mathrm{CO}_3(\mathrm{~s})$ [molar mass $=106 \mathrm{~g}$ ]
B. 248 g of $\mathrm{Na}_2 \mathrm{O}(\mathrm{s})$ [molar mass $=62 \mathrm{~g}$ ]
C. 2...
MCQ+4 / -12025
7Some Basic Concepts Of Chemistry
On complete combustion, 0.3 g of an organic compound gave 0.2 g of CO\(_2\) and 0.1 g of H\(_2\)O. The percentage
composition of carbon and hydrogen in the compound, respectively is:
composition of carbon and hydrogen in the compound, respectively is:
MCQ+4 / -12024
8Some Basic Concepts Of Chemistry
\(1.0 \mathrm{~g}\) of \(\mathrm{H}_2\) has same number of molecules as in:
MCQ+4 / -12024
9Some Basic Concepts Of Chemistry
The amount of glucose required to prepare \(250 \mathrm{~mL}\) of \(\frac{\mathrm{M}}{20}\) aqueous solution is :
(Molar mass of glucose : \(180 \mathrm{~g} \mathrm{~mol}^{-1}\))
(Molar mass of glucose : \(180 \mathrm{~g} \mathrm{~mol}^{-1}\))
MCQ+4 / -12024
10Some Basic Concepts Of Chemistry
A compound X contains \(32 \%\) of A, \(20 \%\) of B and remaining percentage of C. Then, the empirical formula of \(\mathrm{X}\) is :
(Given atomic masses of A=64 ; B=40 ; C=32 u)
(Given atomic masses of A=64 ; B=40 ; C=32 u)
MCQ+4 / -12024
11Some Basic Concepts Of Chemistry
The highest number of helium atoms is in
MCQ+4 / -12024
12Some Basic Concepts Of Chemistry
1 gram of sodium hydroxide was treated with \(25 \mathrm{~mL}\) of \(0.75 \mathrm{~M} \mathrm{~HCl}\) solution, the mass of sodium hydroxide left unreacted is equal to
MCQ+4 / -12024
13Some Basic Concepts Of Chemistry
The density of 1 M solution of a compound 'X' is 1.25 g mL\(^{-1}\). The correct option for the molality of solution is (Molar mass of compound X = 85 g):
MCQ+4 / -12023
14Some Basic Concepts Of Chemistry
The right option for the mass of \(\mathrm{CO}_{2}\) produced by heating \(20 \mathrm{~g}\) of \(20 \%\) pure limestone is
(Atomic mass of \(\mathrm{Ca}=40\) )
$$\left[\mathrm{CaCO}_{3} \stackrel{1200 \mathrm{~K}}{\longrightarrow} \mathrm{C...
(Atomic mass of \(\mathrm{Ca}=40\) )
$$\left[\mathrm{CaCO}_{3} \stackrel{1200 \mathrm{~K}}{\longrightarrow} \mathrm{C...
MCQ+4 / -12023
15Some Basic Concepts Of Chemistry
What fraction of Fe exists as Fe(III) in Fe0.96O ?
(Consider Fe0.96O to be made up of Fe(II) and Fe(III) only)
(Consider Fe0.96O to be made up of Fe(II) and Fe(III) only)
MCQ+4 / -12022
16Some Basic Concepts Of Chemistry
The density of the solution is 2.15 g mL\(-\)1, then mass of 2.5 mL solution in correct significant figures is :
MCQ+4 / -12022
17Some Basic Concepts Of Chemistry
What mass of 95% pure CaCO3 will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction?
CaCO3(s) + 2HCl(aq) \(\to\) CaCl2(aq) + Co2(g) + 2H2O(l)
[Calculate upto second place of decimal point]
CaCO3(s) + 2HCl(aq) \(\to\) CaCl2(aq) + Co2(g) + 2H2O(l)
[Calculate upto second place of decimal point]
MCQ+4 / -12022
18Some Basic Concepts Of Chemistry
In one molal solution that contains 0.5 mole of a solute, there is
MCQ+4 / -12022