Neet
Rotational Motion
NEET 2024 (Re-Examination)
MCQ+4 / -12024
The radius of gyration of a solid sphere of mass \(5 \mathrm{~kg}\) about \(X Y\) is \(5 \mathrm{~m}\) as shown in figure. The radius of the sphere is \(\frac{5 x}{\sqrt{7}} \mathrm{~m}\), then the value of $x$ is:
