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Electrochemistry

NEET 2022 Phase 1

MCQ+4 / -12022

Given below are half cell reactions:


\(MnO_4^ - + 8{H^ + } + 5{e^ - } \to M{n^{2 + }} + 4{H_2}O\),


\(E_{M{n^{2 + }}/MnO_4^ - }^o = - 1.510\,V\)


\({1 \over 2}{O_2} + 2{H^ + } + 2{e^ - } \to {H_2}O\)


\(E_{{O_2}/{H_2}O}^o = + 1.223\,V\)


Will the permanganate ion, \(MnO_4^ -\) liberate O2 from water in the presence of an acid?

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