Electrochemistry

Calculate emf of the half cell given below :

$$ \begin{aligned} & \mathrm{Pt}(\mathrm{~s})\left|\mathrm{H}_2(\mathrm{~g}, 2 \mathrm{~atm})\right| \mathrm{HCl}(\mathrm{aq}, 0.02 \mathrm{M}) \\ & \mathrm{E}_{\mathrm{H}_2 / \mathrm{H}^{+}}^{\circ}=0 \mathrm{~V} \end{aligned} $$

(Given: $\frac{2.303 R T}{F}=0.059, \log 2=0.3010$ )