Simple Harmonic Motion
MHT CET / Physics / Mechanics / 188 questions
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Practice 188 MHT CET Physics questions from Simple Harmonic Motion. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.
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Simple Harmonic Motion Questions
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1Simple Harmonic Motion
The bob of a pendulum of length ' $l$ ' is pulled aside from its equilibrium position through an angle ' $\theta$ ' and then released. The bob will then pass through its equilibrium position with speed ' $v$ ', where ' $v$ ' equal to ( $g=$...
MCQ+1 / -02024
2Simple Harmonic Motion
A particle performs linear S.H.M. At a particular instant, velocity of the particle is ' $u$ ' and acceleration is ' $\alpha$ ' while at another instant, velocity is ' $v$ ' and acceleration is ' $\beta$ ' $(0<\alpha<\beta)$. The distance b...
MCQ+1 / -02024
3Simple Harmonic Motion
The kinetic energy of a particle, executing simple harmonic motion is 16 J when it is in mean position. If amplitude of motion is 25 cm and the mass of the particle is 5.12 kg , the period of oscillation is
MCQ+1 / -02024
4Simple Harmonic Motion
A horizontal platform with a small object placed on it executes a linear S.H.M. in the vertical direction. The amplitude of oscillation is 40 cm . What should be the least period of these oscillations, so that the object is not detached fro...
MCQ+1 / -02024
5Simple Harmonic Motion
The maximum velocity of a particle, executing S.H.M. with an amplitude 7 mm is $4.4 \mathrm{~ms}^{-1}$
The period of oscillation is $\left[\pi=\frac{22}{7}\right]$
The period of oscillation is $\left[\pi=\frac{22}{7}\right]$
MCQ+1 / -02024
6Simple Harmonic Motion
Starting from mean position, a body oscillates simple harmonically with a period ' $T$ '. After what time will its kinetic energy be $75 \%$ of the total energy? $\left(\sin 30^{\circ}=0.5\right)$
MCQ+1 / -02024
7Simple Harmonic Motion
For a particle executing S.H.M. having amplitude A, the speed of the article is $\left(\frac{1}{3}\right)^{\text {rd }}$ of its maximum speed when the displacement from the mean position is
MCQ+1 / -02024
8Simple Harmonic Motion
The motion of a particle is described by the equation $a=-b x$ where ' $a$ ' is the acceleration, x is the displacement from the equilibrium position and b is a constant. The periodic time will be
MCQ+1 / -02024
9Simple Harmonic Motion
A particle performs linear S.H.M. at a particular instant, velocity of the particle is ' $u$ ' and acceleration is ' $\mathrm{a}_1$ ' while at another instant velocity is ' V ' and acceleration is ' $a_2$ ' $\left(0
MCQ+1 / -02024
10Simple Harmonic Motion
A simple pendulum of length ' $L$ ' has mass ' $M$ ' and it oscillates freely with amplitude ' $A$ '. At extreme position, its potential energy is
MCQ+1 / -02024
11Simple Harmonic Motion
A particle performing S.H.M. starts from equilibrium position and its time period is 12 second. After 2 seconds its velocity is $\pi \mathrm{m} / \mathrm{s}$. Amplitude of the oscillation is $\left[\sin 30^{\circ}=\cos 60^{\circ}=0 \cdot 5,...
MCQ+1 / -02024
12Simple Harmonic Motion
All the springs in fig. (a), (b) and (c) are identical, each having force constant K . Mass attached to each system is ' $m$ '. If $T_a, T_b$ and $T_c$ are the time periods of oscillations of the three systems respectively, then
MCQ+1 / -02024
13Simple Harmonic Motion
A piece of wood has length, breadth and height, ' $a$ ', ' $b$ ' and ' $c$ ' respectively. Its relative density, is ' $d$ '. It is floating in water such that the side ' $a$ ' is vertical. It is pushed down a little and released. The time p...
MCQ+1 / -02024
14Simple Harmonic Motion
A particle is performing S.H.M. about its mean position with an amplitude ' $a$ ' and periodic time ' $T$ '. The speed of the particle when its displacement from mean position is $\frac{a}{3}$ will be
MCQ+1 / -02024
15Simple Harmonic Motion
A particle performing S.H.M. with maximum velocity ' $V$ '. If the amplitude double and periodic time is made, $\left(\frac{1}{3}\right)^{\text {rd }}$ then the maximum velocity is
MCQ+1 / -02024
16Simple Harmonic Motion
Let ' $l_1$ ' be the length of simple pendulum. Its length changes to ' $l_2$ ' to increase the periodic time by $20 \%$. The ratio $\frac{l_2}{l_1}=$
MCQ+1 / -02024
17Simple Harmonic Motion
A particle performs linear S.H.M. When the displacement of the particle from mean position is 3 cm and 4 cm , corresponding velocities are $8 \mathrm{~cm} / \mathrm{s}$ and $6 \mathrm{~cm} / \mathrm{s}$ respectively. Its periodic time is
MCQ+1 / -02024
18Simple Harmonic Motion
A particle starts oscillating simple harmonically from its equilibrium position with time period ' T '. What is the ratio of potential energy to kinetic energy of the particle at time $t=\frac{T}{12}$ ? $$\left(\sin \left(\frac{\pi}{6}\righ...
MCQ+1 / -02024
19Simple Harmonic Motion
A simple pendulum of length ' $l$ ' has a brass bob attached at its lower end. It's period is ' T '. A steel bob of the same size, having density ' $x$ ' times that of brass, replaces the brass bob. Its length is then so changed that the pe...
MCQ+1 / -02024
20Simple Harmonic Motion
The maximum velocity of a particle performing S.H.M. is '\(\mathrm{V}\)'. If the periodic time is made \(\left(\frac{1}{3}\right)^d\) and the amplitude is doubled, then the new maximum velocity of the particle will be
MCQ+1 / -02023
21Simple Harmonic Motion
A rubber ball filled with water, having a small hole is used as the bob of a simple pendulum. The time period of such a pendulum
MCQ+1 / -02023
22Simple Harmonic Motion
A particle is vibrating in S.H.M. with an amplitude of \(4 \mathrm{~cm}\). At what displacement from the equilibrium position is its energy half potential and half kinetic?
MCQ+1 / -02023
23Simple Harmonic Motion
A spring has a certain mass suspended from it and its period for vertical oscillations is '\(T_1\)'. The spring is now cut in to two equal halves and the same mass is suspended from one of the halves. The period of vertical oscillations is ...
MCQ+1 / -02023
24Simple Harmonic Motion
Two S.H.Ms. are represented by equations \(\mathrm{y}_1=0.1 \sin \left(100 \pi \mathrm{t}+\frac{\pi}{3}\right)\) and \(\mathrm{y}_2=0.1 \cos (100 \pi \mathrm{t})\) The phase difference between the speeds of the two particles is
MCQ+1 / -02023
25Simple Harmonic Motion
The bob of simple pendulum of length '\(L\)' is released from a position of small angular displacement \(\theta\). Its linear displacement at time '\(\mathrm{t}\)' is ( \(\mathrm{g}=\) acceleration due to gravity)
MCQ+1 / -02023
26Simple Harmonic Motion
The displacement of a particle executing S.H.M. is \(x=\mathrm{a} \sin (\omega t-\phi)\). Velocity of the particle at time \(\mathrm{t}=\frac{\phi}{\omega}\) is \(\left(\cos 0^{\circ}=1\right)\)
MCQ+1 / -02023
27Simple Harmonic Motion
A simple pendulum of length '\(l\)' and a bob of mass '\(\mathrm{m}\)' is executing S.H.M. of small amplitude '\(A\)'. The maximum tension in the string will be (\(\mathrm{g}=\) acceleration due to gravity)
MCQ+1 / -02023
28Simple Harmonic Motion
A block of mass '\(M\)' rests on a piston executing S.H.M. of period one second. The amplitude of oscillations, so that the mass is separated from the piston, is (acceleration due to gravity, \(\mathrm{g}=10 \mathrm{~ms}^{-2}, \pi^2=10\) )
MCQ+1 / -02023
29Simple Harmonic Motion
A light spring is suspended with mass \(m_1\) at its lower end and its upper end fixed to a rigid support. The mass is pulled down a short distance and then released. The period of oscillation is \(T\) second. When a mass \(m_2\) is added t...
MCQ+1 / -02023
30Simple Harmonic Motion
A uniform circular disc of mass \(12 \mathrm{~kg}\) is held by two identical springs. When the disc is slightly pressed down and released, it executes S.H.M. of period 2 second. The force constant of each spring is (nearly) (Take $$\pi^2=10...
MCQ+1 / -02023
31Simple Harmonic Motion
A simple pendulum has a time period '\(T\)' in air. Its time period when it is completely immersed in a liquid of density one eighth the density of the material of bob is
MCQ+1 / -02023
32Simple Harmonic Motion
A body of mass \(0.04 \mathrm{~kg}\) executes simple harmonic motion (SHM) about \(\mathrm{x}=0\) under the influence of force \(\mathrm{F}\) as shown in graph. The period of
MCQ+1 / -02023
33Simple Harmonic Motion
A mass \(M\) is suspended from a light spring. An additional mass \(M_1\) added extends the spring further by a distance \(x\). Now, the combined mass will oscillate on the spring with period \(T=\)
MCQ+1 / -02023
34Simple Harmonic Motion
Under the influence of force \(F_1\) the body oscillates with a period \(T_1\) and due to another force \(F_2\) body oscillates with period \(T_2\). If both forces acts simultaneously, then the resultant period is
(consider displacement is ...
(consider displacement is ...
MCQ+1 / -02023
35Simple Harmonic Motion
Four massless springs whose force constants are \(2 \mathrm{~K}, 2 \mathrm{~K}, \mathrm{~K}\) and \(2 \mathrm{~K}\) respectively are attached to a mass \(\mathrm{M}\) kept on a frictionless plane as shown in figure, If mass \(M\) is displac...
MCQ+1 / -02023
36Simple Harmonic Motion
A simple pendulum performs simple harmonic motion about \(\mathrm{x}=0\) with an amplitude '\(\mathrm{a}\)' and time period '\(T\)'. The speed of the pendulum at \(x=\frac{a}{2}\) is
MCQ+1 / -02023
37Simple Harmonic Motion
A particle starts from mean position and performs S.H.M. with period 4 second. At what time its kinetic energy is \(50 \%\) of total energy?
\(\left(\cos 45^{\circ}=\frac{1}{\sqrt{2}}\right)\)
\(\left(\cos 45^{\circ}=\frac{1}{\sqrt{2}}\right)\)
MCQ+1 / -02023
38Simple Harmonic Motion
In a stationary lift, time period of a simple pendulum is '\(\mathrm{T}\)'. The lift starts accelerating downwards with acceleration \(\left(\frac{\mathrm{g}}{4}\right)\), then the time period of the pendulum will be
MCQ+1 / -02023
39Simple Harmonic Motion
The time period of a simple pendulum inside a stationary lift is '\(T\)'. When the lift starts accelerating upwards with an acceleration \(\left(\frac{\mathrm{g}}{3}\right)\), the time period of the pendulum will be
MCQ+1 / -02023
40Simple Harmonic Motion
For a particle executing S.H.M., its potential energy is 8 times its kinetic energy at certain displacement '\(x\)' from the mean position. If '\(A\)' is the amplitude of S.H.M the value of '\(x\)' is
MCQ+1 / -02023
41Simple Harmonic Motion
The upper end of the spring is fixed and a mass '\(m\)' is attached to its lower end. When mass is slightly pulled down and released, it oscillates with time period 3 second. If mass '\(\mathrm{m}\)' is increased by \(1 \mathrm{~kg}\), the ...
MCQ+1 / -02023
42Simple Harmonic Motion
The amplitude of a particle executing S.H.M. is \(3 \mathrm{~cm}\). The displacement at which its kinetic energy will be \(25 \%\) more than the potential energy is
MCQ+1 / -02023
43Simple Harmonic Motion
A simple harmonic progressive wave is represented by \(y=A \sin (100 \pi t+3 x)\). The distance between two points on the wave at a phase difference of \(\frac{\pi}{3}\) radian is
MCQ+1 / -02023
44Simple Harmonic Motion
A body is executing a linear S.H.M. Its potential energies at the displacement '\(\mathrm{x}\)' and '\(\mathrm{y}\)' are '\(\mathrm{E}_1\)' and '\(E_2\)' respectively. Its potential energy at displacement \((\mathrm{x}+\mathrm{y})\) will be
MCQ+1 / -02023
45Simple Harmonic Motion
A particle starts oscillating simple harmonically from its mean position with time period '\(T\)'. At time \(t=\frac{T}{12}\), the ratio of the potential energy to kinetic energy of the particle is $$\left(\sin 30^{\circ}=\cos 60^{\circ}=0....
MCQ+1 / -02022
46Simple Harmonic Motion
In a medium, the phase difference between two particles separated by a distance '\(x\)' is \(\left(\frac{\pi}{5}\right)^{\text {c }}\). If the frequency of the oscillation of particles is \(25 \mathrm{~Hz}\) and the velocity of propagation ...
MCQ+1 / -02022
47Simple Harmonic Motion
The time taken by a particle executing simple harmonic motion of period '\(\mathrm{T}\)', to move from the mean position to half the maximum displacement is
MCQ+1 / -02022
48Simple Harmonic Motion
Two identical springs of constant '\(\mathrm{K}\)' are connected in series and parallel in shown in figure. A mass '\(\mathrm{M}\)' is suspended from them. The ratio of their frequencies is series to parallel combination will be
MCQ+1 / -02021
49Simple Harmonic Motion
A body is executing S.H.M. under the action of force having maximum magntude \(50 \mathrm{~N}\). When its energy is half kinetic and half potential; the magnitude of the force acting on the particle is
MCQ+1 / -02021
50Simple Harmonic Motion
A particle performing linear S.H.M. of amplitude \(0.1 \mathrm{~m}\) has displacement \(0.02 \mathrm{~m}\) and acceleration \(0.5 \mathrm{~m} / \mathrm{s}^2\). The maximum velocity of the particle in \(\mathrm{m} / \mathrm{s}\) is
MCQ+1 / -02021
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