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Mht Cet

Differentiation

MHT CET 2026 11th April Evening Shift

MCQ+2 / -02026
If $x^3 + y^3 = 6$ and $\dfrac{d^2y}{dx^2} \cdot \dfrac{d^2x}{dy^2} = \dfrac{m}{(xy)^n}$, where $m, n \in R$ then $\dfrac{m}{n} = $

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