Mht CetDifferentiationMHT CET 2026 11th April Evening ShiftMCQ+2 / -02026If the derivative of $\tan^{-1}(a + bx)$ with respect to x at $x = 0$ is $1$, then $a^6 - b^3 = $A$3a^2 b - 1$B$-3ab^2 + 1$C$-1 - 3a^2 b$D$1 + 3ab^2$Check AnswerClear SelectionReveal AnswerShow Explanation
