Mht CetDifferential EquationsMHT CET 2026 15th April Morning ShiftMCQ+2 / -02026The solution of the differential equation $x^2 \dfrac{dy}{dx} - xy = 1$ is...A$2xy - 2cx^2 - 1 = 0$B$2xy + 2cx^2 + 1 = 0$C$2xy - 2cx^2 + 1 = 0$D$2x^2 y - 2cx + 1 = 0$Check AnswerClear SelectionReveal AnswerShow Explanation
