Mht CetDifferential EquationsMHT CET 2026 15th April Evening ShiftMCQ+2 / -02026The solution of $\dfrac{\text{d}y}{\text{d}x} = \sin(x + y) + \cos(x + y)$ isA$\log\left[1 + \tan\left(\dfrac{x+y}{2}\right)\right] = y + c$, where c is the constant of integrationB$\log\left[1 - \tan\left(\dfrac{x+y}{2}\right)\right] = y + c$, where c is the constant of integrationC$\log\left[1 + \tan\left(\dfrac{x+y}{2}\right)\right] = x + c$, where c is the constant of integrationD$\log\left[1 - \tan\left(\dfrac{x+y}{2}\right)\right] = x + c$, where c is the constant of integrationCheck AnswerClear SelectionReveal AnswerShow Explanation
