16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T463,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2026 Circle PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2026/mathematics/circle/jt-mr4ofksr","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Mathematics / Circle","hasPart":{"@type":"Question","name":"Mht Cet 2026 Circle PYQ with Solution","text":"The angle between the tangents drawn from the origin to the circle (x-7)^2 + (y+1)^2 = 25 is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"The circle is (x-7)^2+(y+1)^2=25 So its centre is C(7,-1) and its radius is r=5 The tangents are drawn from the origin, so take the external point as O(0,0) Now find the distance from the origin to the centre: OC=\\sqrt{(7-0)^2+(-1-0)^2} OC=\\sqrt{49+1}=\\sqrt{50}=5\\sqrt{2} If tangents are drawn from an external point to a circle, the line joining the external point to the centre bisects the angle between the two tangents. Let the angle between OC and one tangent be \\theta. In the right triangle f..."}}}18:T455,

The circle is

$$ (x-7)^2+(y+1)^2=25 $$

So its centre is

$$ C(7,-1) $$

and its radius is

$$ r=5 $$

The tangents are drawn from the origin, so take the external point as

$$ O(0,0) $$

Now find the distance from the origin to the centre:

$$ OC=\sqrt{(7-0)^2+(-1-0)^2} $$

$$ OC=\sqrt{49+1}=\sqrt{50}=5\sqrt{2} $$

If tangents are drawn from an

Circle

Continue this paper

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