Mht CetCircleMHT CET 2026 19th April Evening ShiftMCQ+2 / -02026A circle passes through the point $(0,1)$ and touches the parabola $y = x^2$ at the point $(1,1)$. The centre of the circle is...A$\left(-\dfrac{1}{2}, -\dfrac{5}{2}\right)$B$\left(\dfrac{1}{2}, -\dfrac{5}{2}\right)$C$\left(\dfrac{1}{2}, \dfrac{5}{4}\right)$D$\left(-\dfrac{1}{2}, \dfrac{5}{4}\right)$Check AnswerClear SelectionReveal AnswerShow Explanation
