Electrochemistry

The $E^0_{\text{cell}}$ of $\text{Al}_{(s)} | \text{Al}^{3+}(1\text{M}) || \text{Pb}^{2+}(1\text{M}) | \text{Pb}_{(s)}$ cell is 1.5 V if $E^0_{\text{Pb}}$ is $-0.14$ V then $E^0_{\text{Al}}$ will be