Mht CetElectrochemistryMHT CET 2026 13th April Morning ShiftMCQ+1 / -02026Calculate the molar conductivity of 0.2 M KCl solution at 298 K ($k = 0.0248 \ \Omega^{-1}$cm$^{-1}$)A$143 \ \Omega^{-1}$ cm$^2$ mol$^{-1}$B$98 \ \Omega^{-1}$ cm$^2$ mol$^{-1}$C$124 \ \Omega^{-1}$ cm$^2$ mol$^{-1}$D$87 \ \Omega^{-1}$ cm$^2$ mol$^{-1}$Check AnswerClear SelectionReveal AnswerShow Explanation
