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MHT CET 2025 21st April Morning Shift

MCQ+2 / -02025

The following is the probability distribution of X


$$ \begin{array}{|c|c|c|c|c|} \hline \mathrm{X} & 0 & 1 & 2 & 3 \\ \hline \mathrm{P}(\mathrm{X}=x) & \frac{1+\mathrm{p}}{5} & \frac{2-2 \mathrm{p}}{5} & \frac{2-\mathrm{p}}{5} & \frac{2 \mathrm{p}}{5} \\ \hline \end{array} $$


\(\text { For a minimum value of } p \text {, the value of } 5 E(X) \text { is }\)

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