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Mht Cet

Probability

MHT CET 2025 21st April Evening Shift

MCQ+2 / -02025

\(\text { The c.d.f. of a discrete random variable } \mathrm{X} \text { is }\)


$$ \begin{array}{|c|c|c|c|c|c|c|c|c|} \hline \mathrm{X} & -3 & -1 & 0 & 1 & 3 & 5 & 7 & 9 \\ \hline \mathrm{~F}(\mathrm{X}=x) & 0.1 & 0.3 & 0.5 & 0.65 & 0.75 & 0.85 & 0.90 & 1 \\ \hline \end{array} $$


Then $\frac{P[X=-3]}{P[X<0]}=$

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