Mht Cet
Probability
MHT CET 2025 21st April Evening Shift
MCQ+2 / -02025
\(\text { The c.d.f. of a discrete random variable } \mathrm{X} \text { is }\)
$$ \begin{array}{|c|c|c|c|c|c|c|c|c|} \hline \mathrm{X} & -3 & -1 & 0 & 1 & 3 & 5 & 7 & 9 \\ \hline \mathrm{~F}(\mathrm{X}=x) & 0.1 & 0.3 & 0.5 & 0.65 & 0.75 & 0.85 & 0.90 & 1 \\ \hline \end{array} $$
Then $\frac{P[X=-3]}{P[X<0]}=$
