Mht CetDifferentiationMHT CET 2025 19th April Morning ShiftMCQ+2 / -02025The derivative of $\tan ^{-1}\left(\sqrt{1+x^2}-1\right)$ isA $\frac{x}{\sqrt{1+x^2}\left(x^2-2 \sqrt{x+1}+1\right)}$B $\frac{x}{\sqrt{1+x^2}\left(x^2-2 \sqrt{1+x^2}+3\right)}$C $\frac{x}{\sqrt{1+x^2}\left(x^2-2 \sqrt{x^2+1}+2\right)}$D $\frac{x}{\sqrt{1+x^2}\left(x^2+2 \sqrt{1+x^2}-3\right)}$Check AnswerClear SelectionReveal AnswerShow Explanation
