Mht Cet
Differentiation
MHT CET 2025 19th April Evening Shift
MCQ+2 / -02025
If $x^{\frac{2}{5}}+y^{\frac{2}{5}}=\mathrm{a}^{\frac{2}{5}}$ then $\frac{\mathrm{d} y}{\mathrm{~d} x}=$
Mht Cet
MHT CET 2025 19th April Evening Shift
If $x^{\frac{2}{5}}+y^{\frac{2}{5}}=\mathrm{a}^{\frac{2}{5}}$ then $\frac{\mathrm{d} y}{\mathrm{~d} x}=$