Mht Cet
Differential Equations
MHT CET 2025 20th April Evening Shift
MCQ+2 / -02025
The solution of $\left(1+y^2\right)+\left(x-\mathrm{e}^{\tan ^{-1} y}\right) \frac{\mathrm{d} y}{\mathrm{~d} x}=0$ is
Mht Cet
MHT CET 2025 20th April Evening Shift
The solution of $\left(1+y^2\right)+\left(x-\mathrm{e}^{\tan ^{-1} y}\right) \frac{\mathrm{d} y}{\mathrm{~d} x}=0$ is